Jumlah 5 suku dari deret 1+√3+3+3√3+... Pake caranya yaaa

1 + V3 + 3 + 3V3+
suku pertama a = 1
rasio r = V3/1 = 3/V3 = V3
Sn = a ( r^n - 1) / (r-1)
S5 = 1 ( V3^5 - 1) / ( V3- 1)
= ( 3^5/2 -1) / (V3-1)
= (9V3 - 1) / ( V3 -1)
= (9V3 - 1) x (V3+1) / (3-1)
= (9.3 +9V3 -V3 - 1) / 2
= (26 +8V3)/2
= 13 + 4V3