Matematika

Pertanyaan

mohon bantu kak please makasi.
mohon bantu kak please makasi.

1 Jawaban

  • Mean=(15x3)+(28x4)+(41x4)+(54x8)+(67x12)+(80x23)+(93x6) / 60
    =45+112+164+432+804+1840+558 /60
    =3955/60=65,92
    Titik tengah median=½. 60=30
    b2=60+61/2=60,5
    c=13
    N=60
    F=19
    f=12
    Median=b2+c(½N-F/f)
    =60,5+13(30-19/12)
    =60,5+11,92
    =72,42
    bo=73,5
    d1=23-12=11
    d2=23-6=17
    l=13
    Mo=bo+(d1/(d1+d2)) x l
    =73,5+(11/11+17). 13
    =73,5+5,11
    =78,61
    Letak Q1 pd frekuensi=¼. 60=15 (48-60)
    Q1=b1+l(iN/4 - F per f)
    =47,5+13(1.60/4 - 11 per 8)
    =47,5+6,5
    =54
    Letak Q2 dr frekuensi=½. 60=30 (61-73)
    Q2=60,5+13(2.60/4 - 19 /12)
    =60,5+11,92
    =72,42
    Letak Q3=¾.60=45 (74-86)
    Q3=73,5+13(3.60/4-31/23)
    =73,5+7,91
    =81,41