tentukan persamaan garis lurus (3,2)dan (5,-1)

y-y1 = x- x1
----- -------
y2-y1. x2-x1

y-2 = x-3
----- -----
-1-2. 5-3

y-2 = x-3
----- ------
-3. 2

2y-4 = -3x+9
2y-4+3x-9=0
2y+3x-13=0

ax+by+c=0
3x+2y-13=0


semoga membantu :)