tentukan persamaan garis lurus melalui (-5,3),m=1/5

y-y1 = m (x-x1)
y-3 = 1/5 (x-(-5))
y-3 = 1/5 (x+5)
y-3 = 1/5x+1
y = 1/5x+1+3
y = 1/5x+4
-------------------*5
5y = x+20
5y-x-20 = 0