Matematika

Pertanyaan

Jika ab = 1, bc = 2, cd = 3, de = 4 dan ea = 6 serta a, b, c, d dan e bilangan positif, maka a + b + c + d + e adalah

2 Jawaban

  • [tex]ab=1[/tex] ⇒ [tex]b= \frac{1}{a} [/tex]

    [tex]bc=2[/tex] ⇒ [tex]c= \frac{2}{b}= \frac{2}{ \frac{1}{a} }=2a[/tex]

    [tex]cd=3[/tex] ⇒ [tex](2a)d=3=\frac{3}{2a}[/tex]

    [tex]de=4[/tex] ⇒ [tex] \frac{3}{2}a(e)=4[/tex]
    [tex]e= \frac{4}{ \frac{3}{2}a } = \frac{8}{3}a [/tex]

    [tex]ea=6[/tex] ⇒ [tex]( \frac{8}{3}a )a=6[/tex]
    [tex] a^{2} = \frac{6}{ \frac{8}{3} }=\frac{9}{4}[/tex]
    [tex]a= \frac{3}{2} [/tex]

    [tex]b= \frac{1}{a}= \frac{1}{ \frac{3}{2} }= \frac{2}{3} [/tex]

    [tex]c=2a=2 \frac{3}{2} =3[/tex]

    [tex]d= \frac{3}{2}a= \frac{3}{2}. \frac{3}{2}= \frac{9}{4} [/tex]

    [tex]e= \frac{8}{3}a= \frac{8}{3}. \frac{3}{2}=4[/tex]

    [tex]a+b+c+d+e= \frac{3}{2}+ \frac{2}{3}+3+\frac{9}{4}+4= \frac{18+8+36+27+48}{12}=\frac{137}{12}[/tex]
  • ab = 1
    b = 1/a

    bc = 2
    (1/a) c = 2
    c/a = 2
    c = 2a

    cd = 3
    (2a) d = 3
    2ad = 3
    d = 3/2a

    de = 4
    (3/2a) e = 4
    e = 4 x 2a/3
    e = 8a/3

    ea = 6
    (8a/3) a = 6
    8a^2 / 3 = 6
    8a^2 = 6 x 3
    8a^2 = 18
    a^2 = 18 / 8
    a^2 = 9 / 4
    a = 3/2

    a sudah dapat, tinggal cari yang lain

    ab = 1
    (3/2) b = 1
    b = 2/3

    bc = 2
    (2/3) c = 2
    c = 2 x 3/2
    c = 3

    cd = 3
    (3) d = 3
    d = 3 / 3
    d = 1

    de = 4
    (1) e = 4
    e = 4

    a + b + c + d + e
    = 3/2 + 2/3 + 3 + 1 + 4
    = 9/6 + 4/6 + 8
    = 13/6 + 48/6
    = 61/6

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