Matematika

Pertanyaan

3log (3x - 1) + 3log ( x + 5) = 3 log 7

1 Jawaban

  • LogAritMa

    ³log (3x - 1) + ³log (x + 5) = ³log 7
    ³log (3x - 1)(x + 5) = ³log 7
    (3x - 1)(x + 5) = 7
    3x² + 14x - 12 = 0

    Rumus abc
    x1.2 = (-b ± √(b² - 4ac))/2a
    x1.2 = (-14 ± √340)/6
    x1.2 = (-14 ± 2√85)/6

    Nilai x yg memenuhi :
    (-7 + √85)/3

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