diketahui g(x)=2x/x+3 ntuk x = -3 dan h(x+1)=3x-1 nilai (g.h-1)(4)=

jawab

g(x) = (2x)/(x+3) , x ≠ -3
 
h(x +1) = 3x-1
h⁻¹ (3x  -1) = x + 1
3x -1 = y
3x = y+1
x = 1/3 (y+1)

h⁻¹ (y) = 1/3 (y+1)  +1
h⁻¹ (x) = 1/3 (x +1) + 1 = 1/3 x +  1/3+ 1 = 1/3 x + 4/3
h⁻¹ (4)  = 1/3 (4) + 4/3 = 8/3
goh⁻¹ (4) =  g{ h⁻¹ (4)} =  g(8/3)
goh⁻¹ (4) =  2(8/3)  / ( 8/3+ 3)
= (16/3) / (17/3)
= 16/17