(x+3)^2=16x menggunakan rumus abc

(x + 3)² = 16x
x² + 6x + 9 = 16x
x² - 10x + 9 = 0

x1 = (10 + √(100 - (4 . 9))) / 2
x1 = (10 + √(100 - 36)) / 2
x1 = (10 + √64) / 2
x1 = (10 + 8) /2
x1 = 18 / 2
x1 = 9

x2 = (10 - √(100 - (4 . 9))) / 2
x2 = (10 - √(100 - 36)) / 2
x2 = (10 - √64) / 2
x2 = (10 - 8) /2
x2 = 2 / 2
x2 = 1

Persamaan Kuadrat.

(x + 3)² = 16x
x² + 6x + 9 - 16x = 0
x² - 10 + 9 = 0 ← Bentuk ax² + bx + c = 0

x₁₂ = [-b ± √(b² - 4ac)] / (2a)
      = {10 ± √[(-10)² - 4(1)(9)]} / [2(1)]
      = (10 ± 8) / 2
x₁ = (10 + 8) / 2 = 9
atau
x₂ = (10 - 8) / 2 = 1