Matematika

Pertanyaan

No 4-17 tolong bantu
No 4-17 tolong bantu

1 Jawaban

  • No. 4
    a=0,111111...
    Kalikan 10
    10a=1,11111...
    Kedua ruas dikurangi a
    10a-a=1,11111... -0,111111...
    9a=1
    a=1/9
    b=0,333333
    Kalikan 10
    10b=3,333333...
    Kedua ruas dikurangi b
    10b-b=3,333333... -0,3333...
    9b=3
    b=3/9=⅓
    ^alogb=^1/9 log ⅓=^3^-2 log 3^-1=-1/-2.³log3=½. 1=½
    No. 5
    ²log(√2+1+√2-1)
    =²log 2√2
    =²log2¹.2^½
    =²log 2^3/2
    =3/2.²log2=3/2.1=3/2
    No.6
    Log y¹.y^½ + log x^½ + log x²y per log xy
    =log y^3/2.x^½.x²y per log xy
    =log x^5/2.y^5/2 per log xy
    =log (xy)^5/2 per log xy
    =^xy log (xy)^5/2
    =5/2.^xy log xy
    =5/2.1=5/2
    No. 7
    2¹=³log ²log x
    ³log ²log x=2
    ²log x=3²
    ²log x =9
    x=2^9=512
    No. 8
    Log 2x=1
    2x=10¹
    2x=10
    x=5
    ^25 log 5=^5² log 5¹=½. ^5log 5=½. 1=½
    No. 9
    ^5log75=^5 log 3.5²
    =^5log 3 + 2.^5log 5
    =a+2