Garis Y=mx+n melalui titik (-2,3) dan (4,6. Nilai 2m+n=

Persamaan Garis Lurus.

x₁ = -2 dan y₁ = 3
x₂ = 4 dan y₂ = 6
[tex]\displaystyle \frac{y-y_1}{y_2-y_1}=\frac{x-x_1}{x_2-x_1}\\ \frac{y-3}{6-3}=\frac{x+2}{4+2}\\ 6(y-3)=3(x+2)\\ 6y-18=3x+6\\ 2y-6=x+2\\ y=\frac{1}{2}x+4[/tex]

2m + n = 2(1/2) + 4 = 5