Matematika

Pertanyaan

Tentukan himpunan penyelesaian dari sistem persamaan di linier tiga variabel
2x - 3y - z = 20
X + 2y + z = 26
X + 4y + 2z = 15

2 Jawaban

  • 2x - 3y - z = 20
    x + 2y + z = 26
    x + 4y + 2z = 15


    persamaan 1 & 2

    2x - 3y - z = 20
    x + 2y + z = 26
    ____________+
    3x - y = 46 (… 1)


    persamaan 1 & 3

    2x - 3y - z = 20 |×2|
    x + 4y + 2z = 15 |×1|

    4x - 6y - 2z = 40
    x + 4y + 2z = 15
    _____________+
    5x - 2y = 55 (… 2)

    (… 1) & (… 2)

    3x - y = 46 |×2|
    5x - 2y = 55 |×1|

    6x - 2y = 92
    5x - 2y = 55
    __________-
    x = 37


    substitusi x = 37

    3x - y = 46
    3.37 - y = 46
    111 - y = 46
    -y = 46 - 111
    -y = -65
    y = 65


    substitusi x = 37 y = 65

    x + 4y + 2z = 15
    37 + 4.65 + 2z = 15
    37 + 260 + 2z = 15
    297 + 2z = 15
    2z = 15 - 297
    2z = -282
    z = -141
  • Eliminasi pers i dan ii
    2x - 3y - z =20
    x + 2y + z =26
    _____________-
    x + y = -6 ... (iv)

    Eliminasi pers ii dan iii
    x + 2y + z =26 |×2| 2x + 4y + 2z =52
    x + 4y + 2z =15 |x1 | x + 4y + 2z =15
    ________________________-
    X = 33

    Substitusi pers iv
    X + y = -6
    33 + y =-6
    y = -39

    Substitusi pers ii
    x + 2y + z = 26
    33 + 2(39) + z = 26
    33 + 78 + z = 26
    Z = 26 - 33 -78
    Z = -85

    Hp { 33,39,-85 }

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