persamaan garis lurus melalui titik (3,5)dan tegak lurus garis 2x+y-5=0 adalah,,

tegak lurus → m1.m2=-1
2x+y-5=0
y= -2x +5
m1= -2
m2 = -1/m1 = -1/-2= 1/2
y-y1 = m (x-x1)
2y - 5= 1/2 (x-3)
2y -5 = 1/2 x -3/2
2y = 1/2× -3/2 + 5
2y = 1/2× -7/2
pers 1/2x -2y -7/2 →dikalikan 2 semua
= x -4y -7