Persamaan garis melalui titik (2,-3) garis ×+3y-6=0

x+3y-6 = 0
3y = -x + 6
y = -1/3x + 2
m = -1/3

y-y1 = m(x-x1)
y-(-3) = -1/3(x-2)
y+3 = -1/3x + 2/3
____________ ×3
3y+9 = -x + 2
3y+x+9-2 = 0
3y+x+7 = 0

Semoga membantu yaa:)