jika f(x)=ax+b,f(2)=2,dan f(5)=14.tentukan f(x)

f(x) = ax + b

f(2) = 2
2a + b = 2

f(5) = 14
5a + b = 14

Eliminasikan
5a + b = 14
2a + b = 2
------------------ -
3a = 12
a = 12/3
a = 4

2a + b = 2
2(4) + b = 2
8 + b = 2
b = 2 - 8
b = -6

maka
f(x) = 4x - 6

f(x)=ax+b
f(2)=2a+b=2
f(5)=5a+b=14 –
————————
-3a=-12
a=4

2a+b=2
2.4+b=2
8+b=2
b=2-8
b=-6

f(x)=ax+b
f(x)=4x-6