Matematika

Pertanyaan

cara nomor 18 gimana ya?
cara nomor 18 gimana ya?

1 Jawaban

  • Tak masalah berapapun f(x):
    [tex]f(-\frac{3}{2})=9-6(-\frac{3}{2})-3(-\frac{3}{2})^2 \\ f(-\frac{3}{2})=9+9-3\times\frac{9}{4} \\ f(-\frac{3}{2})=9+9-\frac{27}{4} \\ f(-\frac{3}{2})=\frac{72-27}{4}=\frac{45}{4} \\ f(-\frac{3}{2})=11\frac{1}{4}[/tex]