1per4 +1per6 dikali 2per3

[tex]( \frac{1}{4} + \frac{1}{6} )( \frac{2}{3} ) = \frac{2}{12} + \frac{2}{18} \\ = \frac{(18 \times 2) + (2 \times 12)}{216} \\ = \frac{36 + 24}{216} = \frac{60}{216} = \frac{5}{18} [/tex]