diketahui: Volume tabung= 196,25 cm³ tinggi= 10 cm ditanyakan: A.panjang jari jari kerucut B.luas selimut kerucut C.luas permukaan kerucut

[tex]v = \pi {r}^{2} t \\ 196.25= 3.14 \times {r}^{2} \times 10 \\ {r}^{2} = 196.25 \div 31.4 \\ {r}^{2} = 6.25 \\ r = \sqrt{6.25} = 2.5 \: cm[/tex]
[tex]luas \: selimut \: = 2 \times \pi \times r \times t\\ l = 2 \times 3.14 \times 2.5 \times 10 \\ l = 157 \: {cm}^{2} [/tex]
[tex]luas \: permukaan \\ l = 2 \times \pi \times r \times (t + r) \\ l = 2 \times 3.14 \times 2.5 \times (10 + 2.5) \\ l = 2 \times 3.14 \times 2.5 \times 12.5 \\ l = 196.25 {cm}^{2} [/tex]