4log2+4log2√8-4log√32
Matematika
en1213
Pertanyaan
4log2+4log2√8-4log√32
1 Jawaban
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1. Jawaban Anonyme
Bab Logaritma
Matematika SMA Kelas X
⁴log 2 + ⁴log 2√8 - ⁴log √32 = ⁴log (2 . 2√8 : √32)
= ⁴log (2 . √32 : √32)
= ⁴log 2
= 1/(²log 4)
= 1/(²log 2²)
= 1/2