tolong bantu jawab menggunakan cara terima kasih
Matematika
lilyindahh
Pertanyaan
tolong bantu jawab menggunakan cara terima kasih
1 Jawaban
-
1. Jawaban SadonoSukirno
^tanda pangkat
dijabarin satu2 dulu
-) (4/9)^x²-3
{(2/3)²}^x²-3
(2/3)^2(x²-3)
(2/3)^2x²-6
-) (8/27)^1-x
-) {(2/3)³}^1-x
(2/3)^3(1-x)
(2/3)^3-3x
-) 3/2 = (2/3)^-1
maka jadinya
(2/3)^2x²-6 . (2/3)^3-3x = (2/3)^-1
2x² - 6 + 3 - 3x = -1
2x² - 3x - 3 + 1 = 0
2x² - 3x - 2 = 0
(2x + 1)(x - 2) = 0
2x + 1 = 0
2x = -1
x = -½
x - 2 = 0
x = 2
(x1 - x2)² = (½ - 2)²
= (-3/2)²
= 9/4