Matematika

Pertanyaan

tolong bantu jawab menggunakan cara terima kasih
tolong bantu jawab menggunakan cara terima kasih

1 Jawaban

  • ^tanda pangkat
    dijabarin satu2 dulu
    -) (4/9)^x²-3
    {(2/3)²}^x²-3
    (2/3)^2(x²-3)
    (2/3)^2x²-6
    -) (8/27)^1-x
    -) {(2/3)³}^1-x
    (2/3)^3(1-x)
    (2/3)^3-3x
    -) 3/2 = (2/3)^-1
    maka jadinya
    (2/3)^2x²-6 . (2/3)^3-3x = (2/3)^-1
    2x² - 6 + 3 - 3x = -1
    2x² - 3x - 3 + 1 = 0
    2x² - 3x - 2 = 0
    (2x + 1)(x - 2) = 0
    2x + 1 = 0
    2x = -1
    x = -½
    x - 2 = 0
    x = 2
    (x1 - x2)² = (½ - 2)²
    = (-3/2)²
    = 9/4