1/x + 1/y = 5 2/x - 3/y = -5 dengan cara metode substitusi

x + y = 5 ( pers 1)
2x - 3y = -5 ( pers 2)
x + y = 5
x = 5 - y ( pers 3)

masukkan pers 3 ke pers 2
2x - 3y = -5
2 ( 5 - y ) - 3y = 5
10 - 2y - 3y = 5
-5y = 5 - 10
y = -5 / -5
y = 1 ( pers 4)

Masukkan pers 4 ke pers 1
x + y = 5
x + 1 = 5
x = 5

HP { 5,1}

1/x + 1/y = 5
1/x = 5 - 1/y

Subtitusi 1/x = 5 - 1/y ke persamaan 2/x - 3/y = -5
2(5 - 1/y) - 3/y = -5
10 - 2/y - 3/y = -5
-5/y = -15
y = -5/-15
y = ⅓

Subtitusi y = ⅓ ke pers. 1/x = 5 - 1/y
1/x = 5 - [tex] \frac{1}{^1/_3} [/tex]
1/x = 5 - 3
1/x = 2
x = ½

HP : { ½ , ⅓ }