Matematika

Pertanyaan

Mohon dibantu ya kk:)
Mohon dibantu ya kk:)

1 Jawaban

  • a) 1/5, 1/25,......
    a = 1/5
    r = 1/25 : 1/5 = 1/5
    S tak hingga = 1/5 / (1-1/5) = 1/5 / 4/5 = 1/4

    b) 1/3, 1/15, .....
    a = 1/3
    r = 1/15 : 1/3 = 1/5
    S tak hingga = 1/3 / (1-1/5) = 1/3 / 4/5 = 5/12

    c) 1/2, 1/6, ....
    a = 1/2
    r = 1/6 : 1/2 = 1/3
    S tak hingga = 1/2 / (1-1/3) = 1/2 / 2/3 = 3/4

    d) 3, -1, 1/3,.....
    a = 3
    r = -1/3
    S tak hingga = 3 / (1+1/3) = 3 / 4/3 = 9/4


    Semoga membantu, Tetap semangat
    JKira