Jika f(x) = 6 - 2x - x^2 Koordinat titik balik maks. adalah?

Parabola

f(x) = 6 - 2x - x²

titik balik maksimal : f'(x) = 0
f'(x) = 0
-2 - 2x = 0
2x = -2
x = -1

y = f(-1) = 6 - 2(-1) - (-1)²
y = 7

Koordinat titik balik = (-1,7) ✔