Jika f(x) = 6 - 2x - x^2 Koordinat titik balik maks. adalah?

jawab

f(x) = 6 - 2x -  x²
f' (x) = 0
-2 - 2x =0
-2x = 2
x = -1
f(1) = 6 - 2(-1) - (-1)²
f(1) = 6 +2 - 1
f(1) = 7
titk (x, f(-1))  =( -1,  7)