Matematika

Pertanyaan

jika log(xpangkat2 +7x+20)=1 ,maka (x1 +x2)kuadrat=4x1.x2

1 Jawaban

  • jawab

    log (x² + 7x +20) = 1
    x² + 7x + 20 = 10
    x² + 7x + 10 = 0
    x1 + x2= -7
    x1 . x2 = 10

    (x1 + x2)²   - 4 x1 x2 =
    = 7² - 4(10)
    = 49  -40
    = 9

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